49x^2+210x+225=0

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Solution for 49x^2+210x+225=0 equation: 



49x^2+210x+225=0

a = 49; b = 210; c = +225;
Δ = b2-4ac
Δ = 2102-4·49·225
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-210}{98}=-2+1/7$

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